How do you convert $8^{- \frac{1}{3}} = \frac{1}{2}$ $8^(-1/3) = 1/2$ into log form?

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Answer 1 · 2016-03-07T09:26:01

${log}_{8} (\frac{1}{2}) = - \frac{1}{3}$ $log_8(1/2)=-1/3$

Use the definition of logarithm ${log}_{b} x = n$ $log_bx=n$ means $b^{n} = x$ $b^n=x$

How do you convert 8^(-1/3) = 1/28−13=128^(-1/3) = 1/2 into log form?