How do you convert $(8, \frac{π}{2})$ $(8, pi/2)$ to rectangular form?

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How do you convert $(8, \frac{π}{2})$ $(8, pi/2)$ to rectangular form?

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Answer 1 · 2016-02-11T11:20:16

r = 8 and $θ = \frac{π}{2}$ $theta = pi/2$ . So, $x = r cos (θ) = 8 X 0 = 0 and y = r sin (θ)$ $x = rcos(theta) = 8 X 0 = 0 and y = rsin(theta)$ = 8 X 1 = 8.. Answer: (8, 0).

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How do you convert $(8, \frac{π}{2})$ $(8, pi/2)$ to rectangular form?

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How do you convert $(8, \frac{π}{2})$ $(8, pi/2)$ to rectangular form?