Question

How do you convert `9=(4x+7)^2+(-y+7)^2` into polar form?

Answer 1

`16r^2cos^2theta+r^2sin^2theta+56rcostheta-14rsintheta+89=0`

Explanation:

`9=16x^2+56x+49+y^2-14y+49`

`0=16x^2+56x+y^2-14y+49+49-9`

`0=16x^2+y^2+56x-14y+89`

Now use the formulas
`x=rcos theta and y=rsintheta`

`0=16r^2cos^2theta+r^2sin^2theta+56rcostheta-14rsintheta+89`