How do you convert 9=(x+3)^2+(y-2)^29=(x+3)2+(y−2)2 into polar form?

1 Answer
Ratnaker Mehta
Jul 3, 2016

: r^2+2r(3costheta-2sintheta)+4=0:r2+2r(3cosθ−2sinθ)+4=0.

Explanation:

Simplifying the given eqn., it becomes : x^2+y^2+6x-4y+4=0.:x2+y2+6x−4y+4=0.

To convert this cartsn. eqn. into polar, we use the conversion formula ;x=rcostheta, y=rsintheta, and, x^2+y^2=r^2;x=rcosθ,y=rsinθ,and,x2+y2=r2

Sub.ing, we get the eqn. in polar form as : r^2+2r(3costheta-2sintheta)+4=0:r2+2r(3cosθ−2sinθ)+4=0.

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