How do you convert $e^{3 - 4 i}$ $e^(3-4i)$ into cartesian form?

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Answer 1 · 2016-08-25T16:44:38

$e^{3} (cos 4 - i sin 4) = - 13.13 - i 15.20$ $e^3(cos 4-i sin 4)=-13.13-i 15.20$ ., nearly

$e^{3 - 4 i}$ $e^(3-4i)$

$= e^{3} e^{(- 4) i}$ $=e^3 e^((-4)i)$

$= e^{3} (cos (- 4) + i sin (- 4)$ $=e^3(cos(-4)+i sin (-4)$

$= e^{3} (cos 4 - i sin 4)$ $=e^3(cos 4 - i sin 4)$

$20.0855 (cos ({229.2}^{o}) - i sin ({229.3}^{o}))$ $20.0855(cos (229.2^o)- i sin (229.3^o))$

$= - 13.13 - i 15.20$ $=-13.13-i 15.20$ ., nearly

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How do you convert e^(3-4i)e3−4ie^(3-4i) into cartesian form?