How do you convert $e^{- 4} i$ $e^-4i$ into cartesian form?

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Answer 1 · 2016-10-09T19:06:29

$e^{- 4 i} = cos (- 4) + i sin (- 4)$ $e^(-4i) = cos(-4) + isin(-4)$

Use Euler's equation:

$e^{- 4 i} = cos (- 4) + i sin (- 4)$ $e^(-4i) = cos(-4) + isin(-4)$

How do you convert e^-4ie−4ie^-4i into cartesian form?