How do you convert #e^-4i# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Douglas K. Oct 9, 2016 #e^(-4i) = cos(-4) + isin(-4)# Explanation: Use Euler's equation: #e^(-4i) = cos(-4) + isin(-4)# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 5509 views around the world You can reuse this answer Creative Commons License