How do you convert Hubble's constant?

1 Answer
May 30, 2016

The Hubble's constant #H_0# is 71 km/sec/mega parsec, nearly. See explanation for conversion.

Explanation:

#H_0# km/sec/mega parsec

#=H_0 X 10^(-6)# km/sec/parsec

#=(H_0 X 10^(-6)/206265)=4.85 x 10^(-12)H_0# km/sec/AU

#=(((H_0 X 10^(-6)/206265))/149597871)= 3.24 X 10^(-20)H_0# km/sec/km

#=(((H_0 X 10^(-6)/206265))/149597871)(365.25 X 24 X 3600)#

#=1.02 X 10^(-12)H_0# km/year/km

In this second edition, i convert #H_0 to age of our universe, in the

Hubble way.

The age of our universe is #1/H_0# years, where #H_0# is obtained

in u/year/u, with u some unit of distance, at your choice.

This invariant factor to be applied to the standard #H_0= 71#

km/sec/parsec is #1.02 X 10^(-12)#

Now, #1/(converted H_0)#

#=1/(71 X 1.02 X 10^(-12)) = 1.38 X 10^10# years.

#=13.8# billion years.