How do you convert #r = 1 + 2 sin theta# to rectangular form? Trigonometry The Polar System Converting Between Systems 1 Answer 1s2s2p Mar 12, 2018 #(x^2+y^2-2y)^2=x^2+y^2# Explanation: Multiply each term by #r# to get #r^2=r+2rsintheta# #r^2=x^2+y^2# #r=sqrt(x^2+y^2)# #2rsintheta=2y# #x^2+y^2=sqrt(x^2+y^2)+2y# #x^2+y^2-2y=sqrt(x^2+y^2)# #(x^2+y^2-2y)^2=x^2+y^2# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 11596 views around the world You can reuse this answer Creative Commons License