How do you convert $r = 4$ $r = 4$ into cartesian form?

Question

14355 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-19T16:56:26

$x^{2} + y^{2} = 16$ $x^2+y^2=16$

The relation between polar coordinates $(r, θ)$ $(r,theta)$ and Cartesian coordinates $(x, y)$ $(x,y)$ is given by

$x = r cos θ$ $x=rcostheta$ , $y = r sin θ$ $y=rsintheta$ , $r^{2} = x^{2} + y^{2}$ $r^2=x^2+y^2$ .

Using them $r = 4$ $r=4$ is $r^{2} = 16$ $r^2=16$ or $x^{2} + y^{2} = 16$ $x^2+y^2=16$

which is the equation of circle with radius $4$ $4$ .

How do you convert r = 4r=4 r = 4 into cartesian form?