How do you convert $r = - 4 csc (θ)$ $r = -4csc(theta)$ into cartesian form?

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Answer 1 · 2016-06-01T01:42:38

$y = - 4$ $y=-4$

$(x, y) = (r cos θ, r sin θ)$ $(x, y)=(r cos theta, r sin theta)$ . So,

$r = y csc θ = - - 4 csc θ$ $r = y csc theta=--4 csc theta$ .

As $csc θ$ $csc theta$ cannot be zero, $y = - 4$ $y = -4$ is the cartesian equation.

For detailed discussion on such equations, see

How do you convert r = -4csc(theta)r=−4csc(θ)r = -4csc(theta) into cartesian form?