How do you convert $r = - 5 cos θ$ $r = - 5 Cos theta$ to rectangular form?

Question

8511 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-09T00:12:23

$x^{2} + y^{2} = - 5 x$ $x^2+y^2=-5x$

$x^{2} + y^{2} = r^{2}$ $x^2+y^2=r^2$

$r^{2} = - 5 r cos θ \to$ $r^2=-5rcostheta->$ multiply both sides by r

So $x^{2} + y^{2} = - 5 r cos θ$ $x^2+y^2=-5rcostheta$

Recall that $x = r cos θ$ $x=rcostheta$

So $x^{2} + y^{2} = - 5 x$ $x^2+y^2=-5x$

How do you convert r = - 5 Cos thetar=−5cosθr = - 5 Cos theta to rectangular form?