Question

How do you convert `r=6cos(theta)` to rectangular form?

Answer 1

# x^2 + y^2 = 6x

Explanation:

using the formulae that links Polar to Cartesian coordinates.

`• r^2 = x^2 + y^2`

`• x = rcostheta rArr costheta = x/r`

then here : `r = 6 costheta rArr r = 6 xx x/r`

( multiply both sides by r )

hence `r^2 = 6x`

`rArr x^2 + y^2 = 6x`