How do you convert #r=8cos(theta)# into cartesian form?

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Answer 1 · 2016-07-13T17:30:38

#x^2+y^2=8x#

As relation between Cartesian coordinates #(x,y)# and polar coordinates #(r,theta)# is given by #x=rcostheta# and #y=rsintheta# i.e. #r^2=x^2+y^2#.

As #r=8costheta# can be written as

#r×r=8rcostheta# or

#r^2=8rcostheta# or

#x^2+y^2=8x#

Note - This is the equation of a circle with center at #(4,0)# and radius #4#.