How do you convert r=8cos(theta)r=8cos(θ) into cartesian form?

1 Answer
Jul 13, 2016

x^2+y^2=8xx2+y2=8x

Explanation:

As relation between Cartesian coordinates (x,y)(x,y) and polar coordinates (r,theta)(r,θ) is given by x=rcosthetax=rcosθ and y=rsinthetay=rsinθ i.e. r^2=x^2+y^2r2=x2+y2.

As r=8costhetar=8cosθ can be written as

r×r=8rcosthetar×r=8rcosθ or

r^2=8rcosthetar2=8rcosθ or

x^2+y^2=8xx2+y2=8x

Note - This is the equation of a circle with center at (4,0)(4,0) and radius 44.