How do you convert $r=9/(1+3sin(θ))$ into rectangular form?

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Answer 1 · 2015-11-27T19:21:41

$sqrt(x^2+y^2)+3y=9$

Divide both sides by $r$ :

$1=9/(r+3rsin(theta))$

which you can rewrite as

$r+3rsin(theta)=9$

Since $r=sqrt(x^2+y^2)$ and $y=rsin(theta)$ , the equation becomes

$sqrt(x^2+y^2)+3y=9$

How do you convert r=9/(1+3sin(θ))r=9/(1+3sin(θ)) into rectangular form?