How do you convert $r² = costheta$ into polar form?

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Answer 1 · 2016-05-31T18:52:09

$(sqrt(cos(theta)),theta)$

Standard polar form is of format $(r,theta)$

Where $y=rsin(theta)" and "x=rcos(theta)$
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Notice that in the question we have $r^2 -> r=sqrt(r^2)=sqrt(cos(theta))$

Implying that standard form of $y=rsin(theta)$ translates into $y=sqrt(cos(theta))xxsin(theta)$

Implying that the standard form of $x=rcos(theta)$ translates into $x=sqrt(cos(theta))xxcos(theta)$

So in polar form of type $(r,theta)$ we have:

$(sqrt(cos(theta)),theta)$

How do you convert r² = costhetar² = costheta into polar form?