How do you convert $r sec θ = 3$ $r sec theta = 3$ into cartesian form?

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Answer 1 · 2016-09-30T11:08:35

$x^{2} + y^{2} = 3 x$ $x^2+y^2=3x$

The relation between polar coordinates $(r, θ)$ $(r,theta)$ and Cartesian coordinates $(x, y)$ $(x,y)$ is given by

$x = r cos θ$ $x=rcostheta$ , $y = r sin θ$ $y=rsintheta$ and $r^{2} = x^{2} + y^{2}$ $r^2=x^2+y^2$

Hence $r sec θ = 3$ $rsectheta=3$

$\Leftrightarrow r \times \frac{1}{cos θ} = 3$ $hArrrxx1/costheta=3$

or $r = 3 cos θ$ $r=3costheta$

or $r^{2} = 3 r cos θ$ $r^2=3rcostheta$

or $x^{2} + y^{2} = 3 x$ $x^2+y^2=3x$
graph{x^2+y^2=3x [-3.867, 5.322, -2.057, 2.538]}

How do you convert r sec theta = 3rsecθ=3r sec theta = 3 into cartesian form?