How do you convert $r sin^2 theta=3 cos theta$ to rectangular form?

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Answer 1 · 2016-04-15T17:21:33

$y=+-sqrt(3x)$

$rsin^2 theta = 3cos theta$

$rxxrsin^2 theta =rxx 3cos theta$

$rsinthetaxxrsintheta=3xxrcostheta$

Use formulas $x=rcos theta and y=rsin theta$

$y xx y=3x$

$y^2=3x$

$y=+-sqrt(3x)$

How do you convert r sin^2 theta=3 cos thetar sin^2 theta=3 cos theta to rectangular form?