How do you convert $r= theta - 4sintheta$ to Cartesian form?

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Answer 1 · 2016-12-01T17:21:12

$x^2+y^2=sqrt(x^2+y^2)tan^(-1)(y/x)-4y$

The relation between polar coordinates $(r,theta)$ and Cartesian coordinates $(x,y)$ is given by

$x=rcostheta$ and $y=rsintheta$ i.e. $tantheta=y/x$ and $r^2=x^2+y^2$

Hence $r=theta-4sintheta$

$hArrr^2=rtheta-4rsintheta$

or $x^2+y^2=sqrt(x^2+y^2)tan^(-1)(y/x)-4y$

How do you convert r= theta - 4sintheta r= theta - 4sintheta to Cartesian form?