Question

How do you convert `rsin(theta)=ln(r)+ln[cos(theta)]` into cartesian form?

Answer 1

`y=ln x, x >0`.

Explanation:

The conversion formula is

`r(costheta, sintheta)=(x, y)`.

Here,

`y=lnr=ln(x/r)=ln(r(x/r))=lnx`.