How do you convert $(\sqrt{3}, 1)$ $(sqrt(3), 1)$ to polar form?

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Answer 1 · 2016-10-02T23:29:26

$(2, \frac{π}{6})$ $(2,pi/6)$

$r = sqrt((sqrt3)² + 1²)$

$r = 2$

$theta = tan^-1(1/sqrt3)$

$theta = pi/6$

How do you convert (sqrt(3), 1)(√3,1)(sqrt(3), 1) to polar form?