How do you convert the polar point $(4, - 270^{o})$ $(4,-270^o)$ into rectangular form?

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Answer 1 · 2017-05-11T04:43:56

$(0, 4)$ $(0, 4)$

Polar form $(r, θ)$ $(r, theta)$

Rectangular form: $(r cos θ, r sin θ)$ $(r cos theta, r sin theta)$

$θ = - 270^{\circ} = 90^{\circ}$ $theta = -270^@ = 90^@$

From a trigonometric circle: ${cos 90}^{\circ} = 0; {sin 90}^{\circ} = 1$ $cos 90^@ = 0; " " sin 90^@ = 1$

Rectangular form: $(4 {cos 90}^{\circ}, 4 {sin 90}^{\circ}) = (4 \cdot 0, 4 \cdot 1) = (0, 4)$ $(4 cos 90^@, 4 sin 90^@) = (4*0, 4*1) = (0, 4)$

How do you convert the polar point (4,-270^o)(4,−270o)(4,-270^o) into rectangular form?