How do you convert $θ = \frac{2 π}{3}$ $theta=(2pi)/3$ to rectangular form?

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Answer 1 · 2016-06-14T09:37:48

$y = - \sqrt{3} x$ $y = -sqrt(3) x$

In the pass equations

${ (x = r cos(theta)), (y=r sin(theta)) :}$

making the substitution $theta = (2pi)/3$ we get

$x = -1/2 r$ and $y = sqrt[3]/2 r$ . Elliminating $r$ we obtain

$y = -sqrt(3) x$

How do you convert theta=(2pi)/3θ=2π3theta=(2pi)/3 to rectangular form?