Question

How do you convert `x^2 – 9 = 0` into polar form?

Answer 1

`r^2 = 9cos^2(theta)`

Explanation:

Since `r=xcos(theta)`, you have that `x=r/cos(theta)`. Take the square and substitute, and you'll get

`r^2/cos^2(theta) - 9=0`

which you can rewrite as

`r^2 = 9cos^2(theta)`