How do you convert $x^{2} + y^{2} - 2 a x = 0$ $x^2 + y^2 - 2ax = 0$ to polar form?

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How do you convert $x^{2} + y^{2} - 2 a x = 0$ $x^2 + y^2 - 2ax = 0$ to polar form?

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Answer 1 · 2016-11-07T16:29:38

tHe polar form is $r - 2 a cos θ = 0$ $r-2acostheta=0$

Explanation:

To convert a cartesian equation to a polar equation, we use the following.
$x = r cos θ$ $x=rcostheta$ and $y = sin θ$ $y=sintheta$
$x^{2} + y^{2} - 2 a x = 0$ $x^2+y^2-2ax=0$ $\Rightarrow$ $=>$ $r^{2} {cos}^{2} θ + r^{2} {sin}^{2} θ - 2 a r cos θ = 0$ $r^2cos^2theta+r^2sin^2theta-2arcostheta=0$
Simplifying
$r^{2} - 2 a r cos θ = 0$ $r^2-2arcostheta=0$
$r - 2 a cos θ = 0$ $r-2acostheta=0$

Answer 2 · 2016-11-07T16:37:17

$r = 2 a cos θ$ $r=2acostheta$

Explanation:

Using the pass equations

${(x=rcostheta),(y=rsintheta):}$

$r^2cos^2theta+r^2sin^2theta-2arcostheta=0$ or

$r(r-2acostheta)=0$ so we have

$r=0$ which is a point at the origin of coordinates and

$r=2acostheta$

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How do you convert $x^{2} + y^{2} - 2 a x = 0$ $x^2 + y^2 - 2ax = 0$ to polar form?

2 Answers

Explanation:

Explanation:

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How do you convert x^2 + y^2 - 2ax = 0x2+y2−2ax=0x^2 + y^2 - 2ax = 0 to polar form?

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Explanation:

Explanation:

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How do you convert $x^{2} + y^{2} - 2 a x = 0$ $x^2 + y^2 - 2ax = 0$ to polar form?