How do you convert $x^ 2 + y ^2 + 3y = 0$ to polar form?

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Answer 1 · 2016-08-01T19:02:48

r= -3sin $theta$

Write x= rcos $theta$ and y= r sin $theta$ to have,

$r^2 cos^2 theta +r^2 sin^2 theta +3r sin theta$ =0

$r^2 +3r sin theta$ =0

$r+sin theta$ =0

$r= -3sin theta$

How do you convert x^ 2 + y ^2 + 3y = 0x^ 2 + y ^2 + 3y = 0 to polar form?