Question

How do you convert `x^ 2 + y ^2 + 3y = 0` to polar form?

Answer 1

r= -3sin`theta`

Explanation:

Write x= rcos`theta` and y= r sin `theta` to have,

`r^2 cos^2 theta +r^2 sin^2 theta +3r sin theta`=0

`r^2 +3r sin theta`=0

`r+sin theta`=0

`r= -3sin theta`