How do you convert x^2 + y^2 - 8y = 0x2+y2−8y=0 in polar form?
1 Answer
Jan 14, 2016
r = 8sinthetar=8sinθ
Explanation:
Using the formulae which links Polar and Cartesian coordinates :
x^2 + y^ 2 = r^2 , x = rcostheta , y = rsintheta x2+y2=r2,x=rcosθ,y=rsinθ
rArr x^2+ y^2 - 8y =0 ⇒x2+y2−8y=0 can be rewritten as :
x^2 + y^2 = 8y rArr r^2 = 8r sintheta x2+y2=8y⇒r2=8rsinθ (and dividing both sides by r ) obtain:
r = 8sintheta r=8sinθ
