How do you convert $x=y²-6y+11$ into polar form?

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Answer 1 · 2017-09-12T21:09:47

see below

Use the formulas $x=rcos theta, y=rsin theta$ to substitute into the equation.

That is,

$x=y^2 -6y +11$

$rcos theta = r^2 sin^2 theta -6rsin theta +11$

$0=r^2sin^2 theta-6rsin theta-rcos theta +11$

How do you convert x=y²-6y+11 x=y²-6y+11 into polar form?