How do you convert x/y=8-xxy=8−x into polar form?

1 Answer
Cesareo R.
May 13, 2016

r + (cot(theta)-8)sec(theta)=0r+(cot(θ)−8)sec(θ)=0

Explanation:

The pass equations x = r cos(theta), y = r sin(theta)x=rcos(θ),y=rsin(θ) substituted into the cartesian equation gives:
(r cos(theta))/(r sin(theta)) = 8 - r cos(theta)rcos(θ)rsin(θ)=8−rcos(θ). Simplifiying and solving for rr
r + (cot(theta)-8)sec(theta)=0r+(cot(θ)−8)sec(θ)=0

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