How do you convert $y^{2} = 4 (x + 1)$ $y^2= 4(x+1)$ in polar form?

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Answer 1 · 2016-11-23T16:08:03

By converting cartesian to polar coordinates

Pose:

$x = ρ cos (θ)$ $x=rho cos(theta)$
$y = ρ sin (θ)$ $y=rho sin(theta)$

The equation becomes:

$ρ^{2} {sin}^{2} (θ) = 4 (ρ cos (θ) + 1)$ $rho^2 sin^2(theta) = 4(rho cos(theta) + 1)$

How do you convert y^2= 4(x+1) y2=4(x+1)y^2= 4(x+1) in polar form?