Question

How do you convert `y^2= 4(x+1)` into polar form?

Answer 1

see below

Explanation:

Use the formulas `x=rcos theta, y=r sin theta`

`y^2 = 4(x+1)`

`r^2sin^2 theta=4(rcos theta+1)`

`r^2 sin^2 theta=4rcos theta+4`

`:.r^2 sin^2 theta-4rcos theta-4=0`