Question

How do you convert `-y=3y^2-4x^2 -2x` into a polar equation?

Answer 1

`3r^2sin^2theta + r sin theta -4r^2 cos^2 theta -2 r cos theta = 0`

Explanation:

`3y^2+y-4x^2-2x=0`

Use formulas

`x=rcos theta, y= r sin theta`

`3r^2sin^2theta + r sin theta -4r^2 cos^2 theta -2 r cos theta = 0`