Question

How do you convert `-y=3y^2-x^2` into a polar equation?

Answer 1

`0=3r^2sin^2theta+rsintheta-r^2cos^2theta`

Explanation:

`0=3y^2+y-x^2`

use formulas:
`x=rcostheta and y=rsintheta`

`0=3r^2sin^2theta+rsintheta-r^2cos^2theta`