How do you convert $y = (sqrt(3)/3)x$ into polar form?

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Answer 1 · 2016-01-25T05:48:56

$tan theta=sqrt3/3$

Start from the given $y=sqrt3/3*x$

from the conversion equivalents

$y=r*sin theta$

$x=r*cos theta$

Replace now the variables $x$ and $y$ with the equivalent expressions in terms of $r$ and $theta$

$y=sqrt3/3*x$

$r*sin theta=sqrt3/3*r*cos theta$

Dividing both sides by $r*cos theta$

$(r*sin theta)/(r*cos theta)=(sqrt3/3*r*cos theta)/(r*cos theta)$

$(cancelr*sin theta)/(cancelr*cos theta)=(sqrt3/3*cancel(r*cos theta))/(cancel(r*cos theta))$

$tan theta=sqrt3/3$

Have a nice day !!! from the Philippines...

How do you convert y = (sqrt(3)/3)xy = (sqrt(3)/3)x into polar form?