How do you convert $y = x + x^{2} + 2 y^{2}$ $y=x+x^2+2y^2$ into a polar equation?

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How do you convert $y = x + x^{2} + 2 y^{2}$ $y=x+x^2+2y^2$ into a polar equation?

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Answer 1 · 2016-02-12T14:54:39

x = r cos(theta), y = r sin(theta).
The equation converts to
r = $\frac{sin (θ) - cos (θ)}{1 + s q r e sin (θ)}$ $(sin(theta) - cos(theta)) / (1 + sqresin(theta)$

Explanation:

The given rectangular equation represents an ellipse with center at (- 1/2, 1/4) and axes parallel to axes of coordinates (x, y).

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How do you convert $y = x + x^{2} + 2 y^{2}$ $y=x+x^2+2y^2$ into a polar equation?

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How do you convert y=x+x^2+2y^2 y=x+x2+2y2y=x+x^2+2y^2 into a polar equation?

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How do you convert $y = x + x^{2} + 2 y^{2}$ $y=x+x^2+2y^2$ into a polar equation?