How do you determine if f(x)= x^2+x is an even or odd function?

1 Answer
Nov 17, 2016

I would say neither odd or even.

Explanation:

If it is odd then: f(-x)=-f(x) for example the sine function;
if it is even then f(-x)=f(x) as for the cossine function.
In our case let us choose x=2
f(x)=f(2)=(2)^2+(2)=4+2=6
So, let us check:
f(-x)=f(-2)=(-2)^2+(-2)=4-2=2
-f(x)=-f(2)=-[(2)^2+2]=-6

f(-x)!=f(x)!=-f(x)
So no condition is satisfied!