How do you determine if #f(x) = x^3 - x^7# is an even or odd function?
1 Answer
May 12, 2016
odd function
Explanation:
To determine if a function is even/odd consider the following.
• If f(x) = f( -x) , then f(x) is even
Even functions are symmetrical about the y-axis.
• If f( -x) = - f(x) , then f(x) is odd
Odd functions have symmetry about the origin.
Test for even
#f(-x)=(-x)^3-(-x)^7=-x^3+x^7# Since f(x) ≠ f( -x) , then f(x) is not even.
Test for odd
#-f(x)=-(x^3-x^7)=-x^3+x^7# Since f( -x) = - f(x) , then f(x) is odd.
Here is the graph of f(x). Note symmetry about origin.
graph{x^3-x^7 [-10, 10, -5, 5]}