How do you determine if #f(x)= x^5# is an even or odd function?
1 Answer
Aug 2, 2016
f(x) is an odd function.
Explanation:
To determine if f(x) is even/odd consider the following.
• If f(x)= f( -x) , then f(x) is even
#AAx" in the domain"# Even functions have symmetry about the y-axis.
• If f( -x) = - f(x) , then f(x) is odd
#AAx" in the domain"# Odd functions have half-turn symmetry about the origin.
Test for even
#f(-x)=(-x)^5=-x^5≠f(x)" hence not even"# Test for odd
#-f(x)=-x^5=f(-x)" hence f(x) is an odd function"#
graph{x^5 [-10, 10, -5, 5]}