Question

How do you determine the amplitude, period, and phase shift for `y=sin(x-pi/2)`?

Answer 1

`sin(theta)` has
an amplitude of `1`
a period of `2pi`
and a phase shift of `0`

The only effect of replacing `theta " with " (x-pi/2)`
is to shift the variable to the left by `pi/2`
(e.g.. `sin(x - pi/2) " with " x=pi/2`
is equivalent to `sin(theta) " with " theta=0`)

So
the amplitude remains `1`
the period remains `2pi`
and the phase shift is `-pi/2`