How do you determine the constant of proportionality if y is inversely proportional to x and y = 6 when x = 4?

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How do you determine the constant of proportionality if y is inversely proportional to x and y = 6 when x = 4?

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Answer 1 · 2018-04-09T16:30:56

$k = 24$ $k=24$

Explanation:

$y \propto \frac{1}{x}$ $y∝1/x$ ,

$y = \frac{k}{x}$ $y=k/x$ , where $k$ $k$ is constant

$y = 6$ $y=6$ $x = 4$ $x=4$ so,

$6 = \frac{k}{4}$ $6=k/4$

$6 \cdot 4 = k$ $6*4=k$

$k = 24$ $k=24$

Answer 2 · 2018-04-09T16:41:26

$k = 24$ $k=24$

Explanation:

$the initial statement is y \propto \frac{1}{x}$ $"the initial statement is "yprop1/x$

$to convert to an equation multiply by k the constant$ $"to convert to an equation multiply by k the constant"$
$of variation$ $"of variation"$

$\Rightarrow y = k \times \frac{1}{x} = \frac{k}{x}$ $rArry=kxx1/x=k/x$

$to find k use the given condition$ $"to find k use the given condition"$

$y = 6 when x = 4$ $y=6" when "x=4$

$y = \frac{k}{x} \Rightarrow k = y x = 6 \times 4 = 24$ $y=k/xrArrk=yx=6xx4=24$

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How do you determine the constant of proportionality if y is inversely proportional to x and y = 6 when x = 4?

2 Answers

Explanation:

Explanation:

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