How do you determine the equation of the line passing through (2,6) That is perpendicular to #y=-3x+1#?

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Answer 1 · 2018-04-08T11:00:41

#color(violet)("Equation of the perpendicular line is " 3y = x + 16#

Given #y = -3x + 1#

It is in the form, #y = mx + c# where m is the slope & c the y-intercept.

#:. m = -3#

Slope of perpendicular line #m_1 = -1/m = 1/3#

Equation of perpendicular line passing thru (2,6) is

#(y - y_1) = m * (x - x_1)#

#y - 6 = (1/3) * (x - 2)#

#3y - 18 = x - 2#

#3y = x + 16#