How do you determine the intervals where #f(x)=x^(2/3)+3# is concave up or down?
1 Answer
Oct 25, 2016
Investigate the sign of the second derivative.
Explanation:
The domain of
So the only place where
On
On
Because the concavity does not change, there is no inflection point.
By the way, here is the graph of
graph{y=x^(2/3)+3 [-12.62, 12.69, -2.98, 9.68]}