Question

How do you determine the limit of `(3/x^3 - 6/x^6)` as x approaches 0-?

Answer 1

`3/x^3-6/x^6 = (3x^3-6)/x^6`

Explanation:

So the limit is `-oo` (Doe not exist because as `xrarr0^-`,

`(3x^3-6)rarr-6`

and `x^6rarr0^+`