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How do you determine the missing coordinate P(3, 2) and Q(8,_) if slope is -1?

1 Answer

Jun 15, 2015

Q has coordinates (8,-3)

Explanation:

The slope between two points, P and Q is defined to be
$m = \frac{y_{Q} - y_{P}}{x_{Q} - x_{P}}$ $m= (y_Q - y_P)/(x_Q-x_P)$

Given $P = (3, 2)$ $P=(3,2)$ , $Q = (8, x)$ $Q=(8,x)$ , and $m = - 1$ $m= -1$
we have
$XXXX$ $color(white)("XXXX")$ $- 1 = \frac{x - 2}{8 - 3}$ $-1 = (x-2)/(8-3)$

$\Rightarrow$ $rArr$ $XXXX$ $color(white)("XXXX")$ $x - 2 = - 5$ $x-2 = -5$

$\Rightarrow$ $rArr$ $XXXX$ $color(white)("XXXX")$ $x = - 3$ $x = -3$

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