How do you determine the number of possible triangles and find the measure of the three angles given $a = 6, c = 10, m ∠ A = 45$ $a=6, c=10, mangleA=45$ ?

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Answer 1 · 2018-03-26T06:48:43

Since $sin θ$ $sin theta$ can not have a value more than 1, $(sin 90 = 1)$ $(sin 90 = 1)$ , no triangle is possible with the given measurements.

Given : $a = 6, c = 10, ˆ A = 45^{\circ}$ $a = 6, c = 10, hat A = 45^@$

$\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}$ $sin A / a = sin B / b = sin C / c$

sin C = (c * sin A) / a = (10 ^ sin 45) / 6 = 1.1785#

Since $sin θ$ $sin theta$ can not have a value more than 1, $(sin 90 = 1)$ $(sin 90 = 1)$ , no triangle is possible with the given measurements.

How do you determine the number of possible triangles and find the measure of the three angles given a=6, c=10, mangleA=45a=6,c=10,m∠A=45a=6, c=10, mangleA=45?