How do you determine the slope of the line passing through (3, -1) and (-2,-4)?

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How do you determine the slope of the line passing through (3, -1) and (-2,-4)?

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Answer 1 · 2018-04-02T22:13:59

The slope is $\frac{3}{5}$ $3/5$ .

Explanation:

Use the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$ ,

where,

$m$ $m$ is the slope, $(x_{1}, y_{1})$ $(x_1,y_1)$ is one point, and $(x_{2}, y_{2})$ $(x_2,y_2)$ .

I'm going to use $(3, - 1)$ $(3,-1)$ as $(x_{1}, y_{1})$ $(x_1,y_1)$ , and $(- 2, - 4)$ $(-2,-4)$ as $(x_{2}, y_{2})$ $(x_2,y_2)$ . The points can be reversed and the slope would be the same.

Plug in the known values and solve.

$m = \frac{- 4 - (- 1)}{- 2 - 3}$ $m=(-4-(-1))/(-2-3)$

$m = - \frac{3}{- 5}$ $m=-3/-5$ $\leftarrow$ $larr$ Dividing by two negatives makes a positive.

$m = \frac{3}{5}$ $m=3/5$

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How do you determine the slope of the line passing through (3, -1) and (-2,-4)?

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