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How do you determine the slope of the line passing through (5,-6) and (3,-6)?

1 Answer

MG · Stefan V.

Mar 15, 2018

The slope is zero. The line is the line
$y = - 6$ $y = -6$

Explanation:

Slope:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

Where,

$y_{2} = - 6$ $y_2 = -6$ , $y_{1} = - 6$ $y_1 =-6$

$x_{2} = 3$ $x_2 = 3$ , $x_{1} = 5$ $x_1 = 5$

The result is $0$ $0$ .

Because both $y$ $y$ values are $- 6$ $-6$ , the line must pass through this value, and zero slope means it is parallel to the $x$ $x$ -axis.

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