How do you determine the value of 4 so that (6,4), (9,2) has slope 1/3?

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Answer 1 · 2017-12-27T05:31:20

For the line to have a slope of $1/3$ , $4$ should take the value $1$

The slope of a straight line is $m=1/3$

The line connecting points $(6,4);(9,2)$ cannot have the slope $1/3$

The option open to us is to change the value of $4$ in the point $(6,4)$

Let us assume instead of $4$ , we supply value $n$

Then that point is $(6,n)$ .

The line connecting points $(6,n); (9,2)$ has a slope of $1/3$

We have to find the value of $n$

$m=(y_2-y_1)/(x_2-x_1)$
$(y_2-y_1)/(x_2-x_1)=1/3$

$x_1=6$
$y_1=n$
$x_2=9$
$y_2=2$

$(2-n)/(9-6)=1/3$
$(2-n)/3=1/3$
$2-n=1/3xx3=1$
$-n=1-2=-1$
$n=1$

For the line to have a slope of $1/3$ , $4$ should take the value $1$