How do you determine whether (6,-2) is on the line $y = \frac{1}{2} x - 5$ $y=1/2x-5$ ?

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How do you determine whether (6,-2) is on the line $y = \frac{1}{2} x - 5$ $y=1/2x-5$ ?

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Answer 1 · 2018-03-10T18:43:35

$(6, - 2) is on the line$ $(6,-2)" is on the line"$

Explanation:

$If the point lies on the line then it will satisfy the$ $"If the point lies on the line then it will satisfy the "$
$equation$ $"equation"$

$substitute x = 6 into the equation and if the result is$ $"substitute x = 6 into the equation and if the result is "$
$y= - 2 then (6, - 2) is on the line$ $"y= - 2 then "(6,-2)" is on the line"$

$x = 6 \to y = (\frac{1}{2} \times 6) - 5 = 3 - 5 = - 2$ $x=6toy=(1/2xx6)-5=3-5=-2$

$\Rightarrow (6, - 2) is on the line y = \frac{1}{2} x - 5$ $rArr(6,-2)" is on the line "y=1/2x-5$

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How do you determine whether (6,-2) is on the line $y = \frac{1}{2} x - 5$ $y=1/2x-5$ ?

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How do you determine whether (6,-2) is on the line $y = \frac{1}{2} x - 5$ $y=1/2x-5$ ?