How do you determine whether the function g(x)=-x^2+3x+4g(x)=x2+3x+4 is concave up or concave down?

1 Answer
Jul 27, 2015

Two methods:

Explanation:

Using calculus, to determine concavity, investigate the sign of the second derivative.

g(x) = -x^2+3x+4g(x)=x2+3x+4

g'(x) = -2x+3

g''(x) = -2

Since g''(x) is always negative, the graph of g is concave down on the domain of g.
Which is to say: g is concave down on (-oo, oo).

Using algebra, the graph of this quadratic is a parabola. Since the coefficient of x^2 is negative, the parabola opens downward. It is concave down.