How do you differentiate #-1=y^3/(1+x^2y)#?
1 Answer
Dec 14, 2016
Explanation:
Rearranging,
graph{y(x^2+y^2)+1=0 [-6.37, 6.365, -3.185, 3.185]}
Rearranging,
graph{y(x^2+y^2)+1=0 [-6.37, 6.365, -3.185, 3.185]}